w^2-40j^2+3wj=

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Solution for w^2-40j^2+3wj= equation: 


Simplifying
w2 + -40j2 + 3wj = 0

Reorder the terms:
3jw + -40j2 + w2 = 0

Solving
3jw + -40j2 + w2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-8j + -1w)(5j + -1w) = 0


Subproblem 1
Set the factor '(-8j + -1w)' equal to zero and attempt to solve:

Simplifying
-8j + -1w = 0

Solving
-8j + -1w = 0

Move all terms containing j to the left, all other terms to the right.

Add 'w' to each side of the equation.
-8j + -1w + w = 0 + w

Combine like terms: -1w + w = 0
-8j + 0 = 0 + w
-8j = 0 + w
Remove the zero:
-8j = w

Divide each side by '-8'.
j = -0.125w

Simplifying
j = -0.125w

Subproblem 2
Set the factor '(5j + -1w)' equal to zero and attempt to solve:

Simplifying
5j + -1w = 0

Solving
5j + -1w = 0

Move all terms containing j to the left, all other terms to the right.

Add 'w' to each side of the equation.
5j + -1w + w = 0 + w

Combine like terms: -1w + w = 0
5j + 0 = 0 + w
5j = 0 + w
Remove the zero:
5j = w

Divide each side by '5'.
j = 0.2w

Simplifying
j = 0.2w
Solution
j = {-0.125w, 0.2w}

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